Question #c09f6

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Question #c09f6

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Answer 1 · 2017-09-08T10:35:13

33.34%

Explanation:

To start of,

Concentration of solution by mass percent is equal to mass of solute divided by the mass of solvent multiplied by hundred

$Concentration of solution by mass % = \frac{mass of solute}{mass of solvent} \cdot 100 %$ $"Concentration of solution by mass %" = "mass of solute"/"mass of solvent" *100%$

Mass of solvent is given: 1500 g

Mass of solution is equal to mass of solute added to mass of solvent

$m_{solution} = m_{solvent} + m_{solute}$ $m_"solution" = m_"solvent" + m_"solute"$

$\to m_{solute} = m_{solution} - m_{solvent}$ $rarr m_"solute"=m_"solution"-m_"solvent"$

putting values in:

$m_{solute} = 2000 g - 1500 g = 500 g$ $m_"solute"=2000g-1500g= 500g$

Back to formula

$Concentration of solution by mass % = \frac{mass of solute}{mass of solvent} \cdot 100$ $"Concentration of solution by mass %" = "mass of solute"/"mass of solvent" *100$

$↓$ $darr$

$Concentration of solution by mass % = \frac{500g}{1500g} \cdot 100 % = 33.34 %$ $"Concentration of solution by mass %" = "500g"/"1500g" *100 %= 33.34%$

Hope that this helps. :)

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Question #c09f6

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