How do we represent the reduction of $dichromate$ $"dichromate"$ to $C r^{3 +}$ $Cr^(3+)$ ?

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Answer 1 · 2017-08-31T07:42:42

We gots a formal reduction of $C r (V I +)$ $Cr(VI+)$ to $C r (I I I +)$ $Cr(III+)$ ....

And as always we represent the reduction by conserving mass and charge, and introducing electrons as particles of convenience.....

And thus....

$underbrace(Cr_2O_7^(2-))_"orange red" +14H^(+) +6e^(-) rarr2Cr^(3+) +7H_2O$

Charge is balanced, and mass is balanced, so tick....

And what would we see in such a reduction? Orange-red dichromate is reduced to the green chromic ion..... $underbrace(Cr^(3+))_"green"$

How do we represent the reduction of "dichromate"dichromate"dichromate" to Cr^(3+)Cr3+Cr^(3+)?