Question #c0def

1 Answer
Aug 26, 2017

Deltav >= 3.2 * 10^4 "m s"^(-1)

Explanation:

Start by writing down the equation for the de Broglie wavelength

color(blue)(ul(color(black)(lamda_ "matter" = h/(m * v))))

Here

  • lamda_ "matter" is its de Broglie wavelength
  • h is Planck's constant, equal to 6.626 * 10^(-34)"J s"
  • m is the mass of the particle
  • v is its velocity

Now, the Heisenberg Uncertainty Principle states that it's impossible for us to measure both the position and the momentum of a particle with arbitrarily high precision.

Mathematically, this is expressed using the following inequality

color(blue)(ul(color(black)(Deltax * Deltap >= h/(4pi))))

Here

  • Deltax is the uncertainty in position
  • Deltap is the uncertainty in momentum
  • h is Planck's constant

The uncertainty in momentum will depend on the mass of the particle, m, and on its uncertainty in velocity, Deltav

color(blue)(ul(color(black)(Deltap = m * Deltav)))

This means that you can rewrite the inequality that describes Heisenberg's Uncertainty Principle as

Deltax * m* Deltav >= h/(4pi)" "color(darkorange)("(*)")

Now, the problem tells you that this particle is moving with a velocity of 4 * 10^5 "m s"^(-1) and that its uncertainty in position is equal to its de Broglie wavelength.

This means that you have

Deltax = lamda_"matter"

or

Deltax = h/(m * v)

Plug this into color(darkorange)("(*)") to get

color(red)(cancel(color(black)(h)))/(color(red)(cancel(color(black)(m))) * v) * color(red)(cancel(color(black)(m))) * Deltav >= color(red)(cancel(color(black)(h)))/(4pi)

Since v > 0, you can multiply both sides by v without having to change the sign of the inequality, so

Deltav >= v/(4pi)

Plug in the value you have for the velocity of the particle to get

Deltav >= (color(red)(cancel(color(black)(4))) * 10^5color(white)(.)"m s"^(-1))/(color(red)(cancel(color(black)(4))) * pi)

color(darkgreen)(ul(color(black)(Deltav >= 3.2 * 10^4color(white)(.)"m s"^(-1))))

The answer is rounded to two sig figs, the number of sig figs you have for the velocity of the particle.