Question #c0def
1 Answer
Explanation:
Start by writing down the equation for the de Broglie wavelength
color(blue)(ul(color(black)(lamda_ "matter" = h/(m * v))))
Here
lamda_ "matter" is its de Broglie wavelengthh is Planck's constant, equal to6.626 * 10^(-34)"J s" m is the mass of the particlev is its velocity
Now, the Heisenberg Uncertainty Principle states that it's impossible for us to measure both the position and the momentum of a particle with arbitrarily high precision.
Mathematically, this is expressed using the following inequality
color(blue)(ul(color(black)(Deltax * Deltap >= h/(4pi))))
Here
Deltax is the uncertainty in positionDeltap is the uncertainty in momentumh is Planck's constant
The uncertainty in momentum will depend on the mass of the particle,
color(blue)(ul(color(black)(Deltap = m * Deltav)))
This means that you can rewrite the inequality that describes Heisenberg's Uncertainty Principle as
Deltax * m* Deltav >= h/(4pi)" "color(darkorange)("(*)")
Now, the problem tells you that this particle is moving with a velocity of
This means that you have
Deltax = lamda_"matter"
or
Deltax = h/(m * v)
Plug this into
color(red)(cancel(color(black)(h)))/(color(red)(cancel(color(black)(m))) * v) * color(red)(cancel(color(black)(m))) * Deltav >= color(red)(cancel(color(black)(h)))/(4pi)
Since
Deltav >= v/(4pi)
Plug in the value you have for the velocity of the particle to get
Deltav >= (color(red)(cancel(color(black)(4))) * 10^5color(white)(.)"m s"^(-1))/(color(red)(cancel(color(black)(4))) * pi)
color(darkgreen)(ul(color(black)(Deltav >= 3.2 * 10^4color(white)(.)"m s"^(-1))))
The answer is rounded to two sig figs, the number of sig figs you have for the velocity of the particle.