What mass of lithium carbonate will result, if $87.2 \cdot g$ $87.2*g$ of $L i O H$ $LiOH$ is treated with excess carbon dioxide?

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What mass of lithium carbonate will result, if $87.2 \cdot g$ $87.2*g$ of $L i O H$ $LiOH$ is treated with excess carbon dioxide?

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Answer 1 · 2017-08-23T07:38:18

Approx. $130 \cdot g$ $130*g$ of $lithium carbonate$ $"lithium carbonate"$ will result.....

Explanation:

We need a stoichiometrically balanced equation.....

$C O_{2} (a q) + 2 L i O H (a q) \to L i_{2} C O_{3} (s) + H_{2} O (l)$ $CO_2(aq) + 2LiOH(aq) rarr Li_2CO_3(s) + H_2O(l)$

Is this balanced?

And then we work out the molar equivalence.....

$Moles of lithium hydroxide = \frac{87.2 \cdot g}{23.95 \cdot g \cdot m o l^{- 1}} = 3.64 \cdot m o l .$ $"Moles of lithium hydroxide"=(87.2*g)/(23.95*g*mol^-1)=3.64*mol.$

And given excess carbon dioxide gas, we gets a mass of $\frac{3.64 \cdot m o l}{2} \times 73.89 \cdot g \cdot m o l^{- 1} = 134.5 \cdot g$ $(3.64*mol)/2xx73.89*g*mol^-1=134.5*g$ WITH RESPECT TO lithium carbonate.

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What mass of lithium carbonate will result, if $87.2 \cdot g$ $87.2*g$ of $L i O H$ $LiOH$ is treated with excess carbon dioxide?

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Explanation:

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What mass of lithium carbonate will result, if 87.2*g87.2⋅g87.2*g of LiOHLiOHLiOH is treated with excess carbon dioxide?

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What mass of lithium carbonate will result, if $87.2 \cdot g$ $87.2*g$ of $L i O H$ $LiOH$ is treated with excess carbon dioxide?