What mass of lithium carbonate will result, if $87.2*g$ of $LiOH$ is treated with excess carbon dioxide?

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Answer 1 · 2017-08-23T07:38:18

Approx. $130*g$ of $"lithium carbonate"$ will result.....

We need a stoichiometrically balanced equation.....

$CO_2(aq) + 2LiOH(aq) rarr Li_2CO_3(s) + H_2O(l)$

Is this balanced?

And then we work out the molar equivalence.....

$"Moles of lithium hydroxide"=(87.2*g)/(23.95*g*mol^-1)=3.64*mol.$

And given excess carbon dioxide gas, we gets a mass of $(3.64*mol)/2xx73.89*g*mol^-1=134.5*g$ WITH RESPECT TO lithium carbonate.

What mass of lithium carbonate will result, if 87.2*g87.2*g of LiOHLiOH is treated with excess carbon dioxide?