Question #fc45c

1 Answer
Stefan V.
Aug 21, 2017

"0.133 moles"0.133 moles

Explanation:

The idea here is that you need to use the molar mass of sucrose to calculate the number of moles present in your sample.

You know that sucrose has a molar mass of "342.3 g mol"^(-1)342.3 g mol−1, which means that 11 mole of sucrose has a mass of "342.3 g"342.3 g.

You want to go from grams to moles, so set up the molar mass of the substance as a conversion factor that has moles in the numerator and grams in the denominator.

![https://www.boundless.com/chemistry/textbooks/boundless-chemistry-textbook/mass-relationships-and-chemical-equations-3](https://useruploads.socratic.org/m3cSCdISUmMq4oPZOZVl_slide3.jpe)

You should end up with

45.4 color(red)(cancel(color(black)("g"))) * "1 mole sucrose"/(342.3 color(red)(cancel(color(black)("g")))) = color(darkgreen)(ul(color(black)("0.133 moles sucrose")))

The answer is rounded to three sig figs.

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