How many chlorine atoms are contained in a 2*mol2⋅mol quantity of FeCl_3FeCl3?

2 Answers
Pop Quiz Whiz
Aug 18, 2017

3.6*10^243.6⋅1024 Chlorine atoms.

Explanation:

Each FeCl_3FeCl3 has three Chlorines.
Here, we can use a conversion factor.
(3Cl(3Cl/molecule)*(6.022*10^23⋅(6.022⋅1023 molecules/mol)*(2.0mol)/mol)⋅(2.0mol)
Molecules and molecules cancel out. Moles and moles cancel out.
We are left with:
3Cl*6.022*10^23*2.03Cl⋅6.022⋅1023⋅2.0
Simplifying and giving the answer to 2 significant figures, we get:
3.6*10^243.6⋅1024 Chlorine atoms.

anor277 · Truong-Son N.
Aug 18, 2017

6xxN_A6×NA chlorine atoms, where N_A=6.022xx10^23NA=6.022×1023

Explanation:

If you were asked how many chlorine atoms there were in "1 dozen"1 dozen FeCl_3FeCl3 formula units, I think you would very quickly answer that there were "3 dozen"3 dozen, i.e. 3636 chlorine atoms.

Here you were asked the SAME QUESTION using the mole, N_A=6.022xx10^23*mol^-1NA=6.022×1023⋅mol−1 as your counting unit.

And thus there are ................

2*molxx3*"chlorine atoms/formula unit"xx6.022xx10^23*mol^-12⋅mol×3⋅chlorine atoms/formula unit×6.022×1023⋅mol−1

=??*"chlorine atoms"=??⋅chlorine atoms.

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