Question #6108a
1 Answer
Aug 16, 2017
Explanation:
We're asked to find the mass of the diamond, given its density and volume it occupies.
To do this, we can look at the density equation:
#"density" = "mass"/"volume"#
And since we're solving for the mass, let's rearrange this to solve for mass:
#ul("mass" = ("density")("volume")#
We know:

#"density" = 3.26# #"g/cm"^3# 
#"volume" = 0.326# #"cm"^3#
The mass is therefore
#"mass" = (3.26color(white)(l)"g/"cancel("cm"^3))(0.236cancel("cm"^3)) = color(red)(ulbar(stackrel(" ")(" "0.769color(white)(l)"g"" "))# rounded to
#3# significant figures.