Question #b7542
1 Answer
Aug 12, 2017
Explanation:
We're asked to find the
Since one mole of barium hydroxide contains two moles of
#2xx0.064color(white)(l)"mol/L" = color(red)(ul(0.128color(white)(l)"mol/L"#
Now that we know the
#ul("pOH" = -log["OH"^-]#
So
#"pOH" = -log(color(red)(0.128color(white)(l)M)) = color(green)(ul(2.056#
At
#ul("pH" = 14 -"pOH"#
So
#color(blue)("pH") = 14- color(green)(2.056) = color(blue)(ulbar(|stackrel(" ")(" "11.94" ")|)#
rounded to two decimal places, because the problem gave us the concentration to two significant figures.