What is the #"pH"# for an aqueous solution with #["H"^+] = 7.5 xx 10^(-3) "M"#?

1 Answer
Truong-Son N.
Aug 10, 2017

Well, you ought to memorize that

#"pH" = -log["H"^(+)]#.

Thus, apply the definition to get...

#"pH" = -log(7.5 xx 10^(-3) "M") = ???#

What is another way to write #"M"# units? Do you expect the #"pH"# here to be less than #7#? Why?

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