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Answer 1 · 2017-08-03T15:01:53

$"displacement" = 230$ $"m"$

We're asked to find the displacement of a car after a certain time, given its constant acceleration.

To do this, we can use the kinematics equation

$ul(Deltax = v_(0x)t + 1/2a_xt^2$

Since the car started from rest, the initial velocity $v_(0x)$ is zero, leaving us with

$ul(Deltax = 1/2a_xt^2$

where

$Deltax$ is the change in position (displacement, which is what we're trying to find)
$a_x$ is the constant acceleration (given as $2.0$ $"m/s"^2$ )
$t$ is the time interval (given as $15$ $"s"$ )

Plugging in known values, we have

$Deltax = 1/2(2.0color(white)(l)"m/s"^2)(15color(white)(l)"s")^2 = color(red)(ulbar(|stackrel(" ")(" "230color(white)(l)"m"" ")|)$

rounded to $2$ significant figures.

Answer 2 · 2017-08-03T15:52:11

The displacement is $"225 m"$ .

![https://useruploads.socratic.org/N05GPlprT0yAjHzylKE4_15017753773091702346355.jpg)