Question #702e2
1 Answer
Aug 3, 2017
Explanation:
We're asked to find the hydroxide ion concentration
To do this, we can use the equation
#"pOH" = -log["OH"^- ]#
But rearrange it to solve for
#ul(["OH"^- ] = 10^(-"pOH")#
We're given that
#["OH"^- ] = 10^(-11.25) = color(red)(ulbar(|stackrel(" ")(" "5.6xx10^-12color(white)(l)M" ")|)#
Since the