Question #3ab39

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Answer 1 · 2017-07-31T06:11:10

The volume is $= 25.7 m l$ $=25.7ml$

Let volume of pure acid $(30 %)$ $(30%)$ be $= v m l$ $=vml$

Then,

Volume of $(100 %)$ $(100%)$ acid is $= (60 - v) m l$ $=(60-v) ml$

The mass balance equation with respect to the acid is

$30 v + 100 (60 - v) = 70 \cdot 60$ $30v+100(60-v)=70*60$

Solving this equation for $v$ $v$

$30 v + 6000 - 100 v = 4200$ $30v+6000-100v=4200$

$(100 - 30) v = 6000 - 4200$ $(100-30)v=6000-4200$

$70 v = 1800$ $70v=1800$

$v = \frac{1800}{70} = 25.7 m l$ $v=1800/70=25.7ml$