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Answer 1 · 2017-07-31T10:52:51

$106.67$ $106.67$ ml of water to be added.

Let $x$ $x$ ml of water is added to dilute the acd solution.

Acid content in $35 %$ $35%$ acid solution is $80 \cdot 0.35 = 28$ $80 * 0.35 = 28$ ml

After adding , total quantity of $15 %$ $15%$ acid solution is $80 + x$ $80 +x$ ml

Acid content in $15 %$ $15%$ acid solution is $(80 + x) \cdot 0.15$ $(80+x) * 0.15$ ml

Quantity of acid remains same before and after dilution.

$:. (80+x) * 0.15 =28 or 80 +x = 28/0.15 = 186 2/3$

$x = 186 2/3 - 80 = 106 2/3 ~~ 106.67$ ml

$106.67$ ml of water to be added [Ans]