How many aluminum-based electrons are present in a salt where there is an 81*g mass of aluminum ions....?

1 Answer
anor277
Jul 26, 2017

How many aluminum-based electrons in a salt where there is an 81*g mass of aluminum ions....?

Explanation:

Well, we take the quotient, (81*g)/(27*g*mol^-1)=3*mol.

And thus there are 3 *mol of aluminum ions, and since there are 10 electrons per Al^(3+) ions (for Al, Z=13), there are 30*mol of aluminum electrons.

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