How many moles of iron oxide are present in a mass of #16*kg#?

1 Answer
anor277
Jul 25, 2017

Well the molar mass of ferric oxide, #Fe_2O_3#, is #159.69*g*mol^-1#....

Explanation:

But iron has a particularly rich oxidation chemistry. We don't know whether all the #16*kg# mass was ferric oxide, or ferrous oxide, or #Fe_3O_4# or hydrous iron oxides.....Clearly you can work out the molar quantity if all the rust is present as #Fe_2O_3#....

#"Moles of ferric oxide"=(16xx10^3*g)/(159.69*g*mol^-1)=??mol.#

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