Why does oxygen have a lower ionization energy than oxygen?

1 Answer
Jul 24, 2017

Because nitrogen does not have any paired valence #2p# electrons that can be removed, while oxygen does.

Coulombic repulsion energy decreases the energy input required to remove a #2p# valence electron from #"O"# atom, i.e. decreases the ionization energy of #"O"# atom compared to #"N"# atom.


Write out the electron configurations.

#"N"#: #1s^2 2s^2 color(red)(2p^3)#

#ul(uarr color(white)(darr))" "ul(uarr color(white)(darr))" "ul(uarr color(white)(darr))#
#underbrace(" "" "" "" "" "" "" "" ")#
#" "" "" "2p#

#ul(uarr darr)#
#2s#

#"O"#: #1s^2 2s^2 color(red)(2p^4)#

#ul(uarr color(red)(darr))" "ul(uarr color(white)(darr))" "ul(uarr color(white)(darr))#
#underbrace(" "" "" "" "" "" "" "" ")#
#" "" "" "2p#

#ul(uarr darr)#
#2s#

You can see that oxygen has a paired #2p# valence electron. That adds electron repulsion, which makes it easier for the electron to get removed.

Thus, oxygen atom has a lower (less positive) ionization energy than nitrogen atom.