Question #c376a

1 Answer
Junaid Mirza
Jul 22, 2017

5.64g

Explanation:

34g of text(H)_2text(S) contains 6.022×10^23 molecules of text(H)_2text(S)

Mass of 1.0×10^23 molecules of text(H)_2text(S) is = (1.0×10^23×34)/(6.022×10^23) = 5.64g

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