Question #fb84b

1 Answer
Oscar L. ยท Stefan V.
Jul 22, 2017

Good catch,the book should have included the solution species "Sn"^{2+}.

Explanation:

The iron metal is not in solution and thus should still be left out. Thus, properly,

E=E^0-{RT}/{6F}ln({["Sn"^{4+}]^3}/{["Sn"^{2+}]^3["Fe"^{3+}]^2})

Note that the tin ion concentrations can be rendered as a ratio between oxidized and reduced solution species:

E=E^0-{RT}/{6F}ln[ { ( (["Sn"^{4+}])/(["Sn"^{2+}]))^3}/{["Fe"^{3+}]^2}]

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