Question #1ad1b
1 Answer
Explanation:
Let use setup some variables to describe the problem:
{ (d, "total distance (or displacement) travelled"), (t_1, "time taken for first part of the journey"), (t_2, "time taken for second part of the journey"), (v_2, "velocity for second part of the journey") :}
For the first part of the Journey:
{ (s, = 1/3d), (u, = v_1), (t, = t_1) :} Applying
s=ut we have:
1/3d = v_1 t_1 ..... [A]
For the second part of the Journey:
{ (s, = 2/3d), (u, = v_2), (t, = t_2) :} Applying
s=ut we have:
2/3d = v_2 t_2 ..... [B]
For the overall Journey:
{ (s, = d), (u, = 2v_1), (t, = t_1+t_2) :} Applying
s=ut we have:
d = 2v_1(t_1+ t_2 ) ..... [C]
From [A] and [C] we have:
d = 3v_1 t_1 = 2v_1(t_1+ t_2 )
:. 3 t_1 = 2t_1+ 2t_2
:. t_1 = 2t_2
So then from [C] we get:
d = 2v_1(2t_2+ t_2 ) = 6v_1t_2
Inserting into [B] we then have:
2/3 * 6v_1t_2 = v_2 t_2
:. v_2 = 2/3 * 6v_1 = 4v_1
