Question #99452

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Answer 1 · 2017-07-20T14:31:24

17 %

Start with the equation:

$sf(CaCO_(3(s))rarrCaO_((s))+CO_(2(g)))$

This tells us that:

1 mole $rarr$ 1 mole + 1mole

Convert moles to grams $rArr$

100g $rarr$ 56g + 44g

$:.$ 10g $rarr$ 5.6g + 4.4g

This means that 12g of the impure sample must contain 10g of $sf(CaCO_3)$ and 2g of impurity.

$:.$ % impurity = $sf((2)/12xx100=17)$