Question #21724

Question

2084 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-05T05:14:51

The basicity of #H_2SO_4# is 2.

Molarity of #H_2SO_4# is 0.1M

So its normalty will be #0.2N#

Again

The basicity of #NaOH# is 1.

Molarity of #NaOH# is 0.1M

So its normalty will be #0.1N#

Now 100mL 0.1M #H_2SO_4# or 0.2N #H_2SO_4equiv# 20mL #1N# #H_2SO_4#

And 500mL 0.1M #NaOH# or 0.1N #NaOHequiv# 50mL #1N# #NaOH#

So #(50-20)=30mL# #1N# #NaOH# will be excess reactant left .

If the normality of final mixtureof volume (100+500)=600mL be #xN# then

#600xx x=30xx1#

#=>x=30/600=0.05N#