Question #21724

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Answer 1 · 2017-08-05T05:14:51

The basicity of $H_2SO_4$ is 2.

Molarity of $H_2SO_4$ is 0.1M

So its normalty will be $0.2N$

Again

The basicity of $NaOH$ is 1.

Molarity of $NaOH$ is 0.1M

So its normalty will be $0.1N$

Now 100mL 0.1M $H_2SO_4$ or 0.2N $H_2SO_4equiv$ 20mL $1N$ $H_2SO_4$

And 500mL 0.1M $NaOH$ or 0.1N $NaOHequiv$ 50mL $1N$ $NaOH$

So $(50-20)=30mL$ $1N$ $NaOH$ will be excess reactant left .

If the normality of final mixtureof volume (100+500)=600mL be $xN$ then

$600xx x=30xx1$

$=>x=30/600=0.05N$