Question #0cba7

1 Answer
David G.
Jul 15, 2017

The yield will be #2# #mol# of #H_2O#.

Explanation:

First we need to write a balanced chemical equation:

#2H_2+O_2=2H_2O#

In this case, the #O_2# will be the limiting reagent: we need #2# #mol# of #H_2# for each mole of #O_2#, but we have 4. There will be some #H_2# left over unreacted.

We know from the balanced equation that #1# #mol# of #O_2# will yield #2# #mol# of #H_2O#, and since we have #1# #mol# of #O_2# the yield will be #2# #mol# of #H_2O#.

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