Given the enthalpy and entropy change of a natural phase transition, derive an expression for the normal boiling point of any substance? Hint: consider that the change in Gibbs' free energy is zero for two phases in equilibrium.
1 Answer
Jul 13, 2017
The hint tells you exactly what to do. Consider the relationship between the Gibbs' free energy, enthalpy, and entropy:
#DeltaG = DeltaH - TDeltaS#
At equilibrium (more specifically, phase equilibrium at constant temperature and pressure!),
#DeltaG_(vap) = 0 = DeltaH_(vap) - T_bDeltaS_(vap)#
#=> color(blue)(T_b = (DeltaH_(vap))/(DeltaS_(vap)))# ,where
#T_b# is the boiling point.
That is, you are somewhere on the green curved dotted line on a phase diagram:
Once you obtain the temperature in