Question #886d1

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Question #886d1

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Answer 1 · 2017-07-09T18:04:59

$345.80 g$ $345.80g$

Explanation:

$\frac{7.71 \cdot 10^{24}}{6.02 \cdot 10^{23}} = 12.807309$ $(7.71*10^24)/(6.02*10^23)=12.807309$ moles of Al

$\frac{Mass}{Molar mass} = Number of moles$ $("Mass")/("Molar mass")="Number of moles"$ , $Mass = (Number of moles) \cdot (Molar mass)$ $"Mass"=("Number of moles")*("Molar mass")$

Molar mass of Al $\approx$ $~~$ 27.0

$27 \cdot 12.807308 \approx 345.80 g$ $27*12.807308~~345.80g$

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Question #886d1

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