For Z=57, what is the element, and what is its electronic configuration?

1 Answer
anor277
Jul 5, 2017

Got a Periodic Table............?

Explanation:

I actually happen to know this one, because I did a lot of work with lanthanides, and actinides. Anyway, Z=57 SPECIFIES the element "lanthanum". And thus the electronic configuration has an xenon core (Xe, Z=54), i.e. [Xe]5d^(1)6s^(2). Lanthanum usually adopts the +III oxidation state, i.e. {[Xe]}^(3+).....

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