In one mole of glucose, how many oxygen atoms are present?

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Answer 1 · 2017-07-02T08:47:13

In glucose, $C_6H_12O_6$ .....I gets $180.16*g$ of glucose.

$"Moles of oxygen atoms"$ $=$ $6xx"moles of glucose"$ . Why? Because CLEARLY, each mole of glucose, $C_6H_12O_6$ contains $6*mol$ oxygen atoms.

Note that I am labouring the point that we deal with OXYGEN ATOMS , NOT OXYGEN MOLECULES.

$96*g$ oxygen is a molar quantity of $(96*g)/(16*g*mol^-1)=6*mol$ with respect to oxygen atoms.

And of course if there are $6*mol$ oxygen atoms, there must be $1*mol$ glucose. Agreed?

We are not quite finished because we were asked for the mass, and so we multiply the molar quantity by the molar mass of glucose.....

$1*molxx180.16*g*mol^-1=180.16*g$ .

Capisce?