How many hydrogen atoms are present in an #18*mL# volume of water?

1 Answer
anor277
Jul 1, 2017

A lot.........

Explanation:

We have #2xxN_A# hydrogen atoms in an #18*mL# volume of water, where #N_A="Avogadro's Number"#, #6.022xx10^23*mol^-1#. Why?

Given that #rho_"water"=1*g*mL^-1#, we have a mass of #1*cancel(mL)xx1*g*cancel(mL^-1)=18*g#.......

And thus a molar quantity of #2*H*mol^-1xxN_A=1.204xx10^24# #"individual hydrogen ATOMS......."#

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