Question #81dd7

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Question #81dd7

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Answer 1 · 2017-06-30T16:37:05

The first must be reversed (cool rhyme!)

Explanation:

When you "add together" two or more chemical equations, it goes similarly as algebra: equal quantities on opposite sides of either reaction can cancel out.

Here's what I mean by this:

Our two equations are

$2 {NO}_{2} (g) \to 2 NO (g) + O_{2} (g)$ $color(red)(2"NO"_2(g)) rarr color(blue)(2"NO"(g) + "O"_2(g))$

$N_{2} O_{4} (g) \to 2 NO (g) + O_{2} (g)$ $color(blue)("N"_2"O"_4(g)) rarr color(red)(2"NO"(g) + "O"_2(g))$

Here, there must be two duplicate quantities is a given color to cancel out. As you may see, neither red nor blue contains a duplicate species. However, if we reversed the first equation, we would then have

$cancel(color(red)(2"NO"(g))) + cancel(color(red)("O"_2(g))) rarr color(blue)(2"NO"_2(g))$

$color(blue)("N"_2"O"_4(g)) rarr cancel(color(red)(2"NO"(g))) + cancel(color(red)("O"_2(g)))$

Two quantities can cancel out, leaving behind the blue equation:

$color(blue)("N"_2"O"_4(g) rarr 2"NO"_2(g)$

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Question #81dd7

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