Question #6ca10

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Question #6ca10

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Answer 1 · 2017-06-29T01:18:56

$78" m"$ .

Explanation:

Given function is

$s(t)=5t^2+t+2$

Distance covered in $t=1" s"$
$s(1)=5(1)²+(1)+2=8" m"$

Distance covered in $t=4" s"$
$s(4)=5(4)²+(4)+2=86" m"$

Distance covered in the given time interval $=86-8=78" m"$

Answer 2 · 2017-06-29T01:25:13

$78$ $"m"$

Explanation:

We're given an equation for distance, and we're asked to find the distance traveled on the interval $t in [1color(white)(l)"s", 4color(white)(l)"s"]$ .

To do this, let's find the distance covered at each of these times, and find the difference between them.

Plugging in $1$ for $t$ :

$s(1) = 5(1)^2 + (1) + 2 = color(red)(8$ $color(red)("m"$

And then plugging in $4$ :

$s(4) = 5(4)^2 + (4) + 2 = color(green)(86$ $color(green)("m"$

The distance it traveled in this time interval is thus

$"Distance" = s(4) - s(1) = color(green)(86$ $color(green)("m"$ $- color(red)(8$ $color(red)("m"$ $= color(blue)(78$ $color(blue)("m"$

Thus from time $t = 1$ $"s"$ to $t = 4$ $"s"$ , the object traveled a distance of $color(blue)(78$ $sfcolor(blue)("meters"$ .

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Question #6ca10

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