If we require #445*g# of copper metal, what mass of #CuFeS_2# ore do we need?

1 Answer
anor277
Jun 17, 2017

Good question! We need approx. #1.3*kg# of ore.....

Explanation:

We want #(445*g)/(63.55*g*mol^-1)=7.00*mol# #"copper metal"#.

Given that we have #CuFeS_2#, we need AT LEAST #7.00*mol# of this ore.........

i.e. a mass of #183.54*g*mol^-1xx7.00*mol=??*g#.

Related questions
See all questions in Percent Composition
Impact of this question
1774 views around the world
You can reuse this answer
Creative Commons License