A train is moving at a constant velocity of $"5 m/s"$ . After it exists a tunnel, it starts to accelerate with an acceleration of $"9 m/s"^2$ for $"5 s"$ . What is the velocity of the train after $"5 s"$ ?

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Answer 1 · 2017-06-14T22:33:11

$50$ $"m/s"$

We're asked to find the velocity of the train after $5$ $"s"$ with a given initial velocity and acceleration.

To solve this, we can use the equation

$v_x = v_(0x) + a_xt$

where

Plugging in known values, we have

$v_x = 5"m/s" + (9"m/s"^2)(5"s") = color(red)(50$ $color(red)("m/s"$

The final velocity (the velocity at time $t = 5$ $"s"$ ) is thus $color(red)(50$ meters per second.

A train is moving at a constant velocity of "5 m/s""5 m/s". After it exists a tunnel, it starts to accelerate with an acceleration of "9 m/s"^2"9 m/s"^2 for "5 s""5 s". What is the velocity of the train after "5 s""5 s" ?