Question #e9b89
1 Answer
Here's what I got.
Explanation:
The molar mass of a compound is essentially the mass of
You know that
#(color(blue)(?)color(white)(.)"g")/"1 mole" -># the molar mass of the compound
equivalent to
#"260 g"/"10 moles"#
Set up the equation as
#(color(blue)(?)color(white)(.)"g")/"1 mole" = "260 g"/"10 moles"#
Rearrange to find
#color(blue)(?) = (1 color(red)(cancel(color(black)("mole"))))/(10color(red)(cancel(color(black)("moles")))) * "260 g"#
#color(blue)(?) = "26 g"#
So, if
#color(darkgreen)(ul(color(black)("molar mass" = "26 g mol"^(-1))))#
I'll leave the answer rounded to two sig figs, but keep in mind that you only have one significant figure for the number of moles present in your sample.