Which option contains a $2g$ mass of sodium atoms.... $1.$ $5.24xx10^22"sodium atoms?"$ $2.$ $6.022xx10^24"sodium atoms?"$ $3.$ $3.12xx10^23"sodium atoms?"$ $4.$ $5.24xx10^22*"sodium atoms?"$

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Answer 1 · 2017-06-08T19:41:14

I would say $"option 1........"$

We know that $1*mol$ contains $6.022xx10^23$ individual sodium atoms, and has a mass of $22.99*g$ .

And thus for $1.$ there is a $2*g$ mass of $Na$ .

For $2.$ there is a $22.99*g$ mass of $Na$ .

For $3.$ there is a ..............................

$(3xx10^23*"sodium atoms")/(6.022xx10^23*"sodium atoms"*mol^-1)xx22.99*g*mol^-1$ mass of $Na$ , approx. $11.5*g$ .

For $4.$ there is a $8*g$ mass of sodium............

And so, clearly,..................Capisce?

Which option contains a 2*g2*g mass of sodium atoms.... 1.1. 5.24xx10^22*"sodium atoms?"5.24xx10^22*"sodium atoms?" 2.2. 6.022xx10^24*"sodium atoms?"6.022xx10^24*"sodium atoms?" 3.3. 3.12xx10^23*"sodium atoms?"3.12xx10^23*"sodium atoms?" 4.4. 5.24xx10^22*"sodium atoms?"5.24xx10^22*"sodium atoms?"