How many "neutrons", massive, neutrally charged nuclear particles, are present in a 2*mol quantity of water?

1 Answer
anor277
Jun 5, 2017

Well, there are 2*mol of water.........and approx. 96xx10^23 individual neutrons.

Explanation:

And in each water molecule, i.e. ""^1H_2""^16O, where we treat the water molecule as AN ISOTOPOMER than contains "8 neutrons", clearly there are 8*mol of neutrons.

And a mole, "Avogadro's Number", specifies N_A, 6.022xx10^23 individual items of stuff. So we have approx. 16xxN_A~=96xx10^23 individual neutrons.

I really can use mental arithmetic here; the numbers are so impossibly large that "near enuff is good enuff".

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