What is the mass of a SINGLE $^{32} S$ $""^32S$ atom?

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Answer 1 · 2017-06-01T16:40:40

$Mass of ONE atom of sulfur \equiv 5.31 \times 10^{- 23} \cdot g$ $"Mass of ONE atom of sulfur"-=5.31xx10^-23*g$

Well we know that $1 \cdot m o l$ $1*mol$ of $^{32} S$ $""^32S$ has a mass of $32 \cdot g$ $32*g$ .

$32 \cdot g$ $32*g$ .

And so we take the quotient..............

$=(32*g*cancel(mol^-1))/(6.022xx10^23*cancel(mol^-1))=5.31xx10^-23*g$ .

What is the mass of a SINGLE ""^32S32S""^32S atom?