What mass is associated with $5.74xx10^22$ $"titanium atoms"$ ?

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Answer 1 · 2017-06-01T12:09:15

Approx. $5*g$ ...........

By definition, a $47.9*g$ mass of titanium contains $N_A$ $"titanium atoms"$ , i.e. $6.022xx10^23$ individual titanium atoms.

And so we work out the molar quantity of titanium atoms present:

$(5.74xx10^22*"titanium atoms")/(6.022xx10^23*"titanium atoms"*mol^-1)=0.0953*mol$ .

And then we multiply the molar quantity by the molar mass:

$0.0953*molxx47.9*g*mol^-1=??*g$ .

Capisce?

What mass is associated with 5.74xx10^225.74xx10^22 "titanium atoms""titanium atoms"?