Question #98339

Question

Question #98339

2 Answers

Impact of this question

1702 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-01T07:44:23

$n (O_{2}) : n (S O_{2}) = 2 : 1$ $n(O_2):n(SO_2) = 2:1$

Explanation:

Molar mass of $O_{2}$ $O_2$ : $2 \cdot 16 = 32$ $2*16=32$ (g/mol)
Molar mass of $S O_{2}$ $SO_2$ : $1 \cdot 32$ $1*32$ (one sulfur atom) $+ 2 \cdot 16$ $+ 2*16$ (two oxygen atoms) $= 64$ $= 64$ (g/mol)

Number of molecules in each gram of substance:
$O_{2}$ $O_2$ : $\frac{1}{32}$ $1/32$
$S O_{2}$ $SO_2$ : $\frac{1}{64}$ $1/64$

$\frac{n (O_{2})}{n (S O_{2})} = \frac{\frac{1}{32}}{\frac{1}{64}} = \frac{2}{1}$ $(n(O_2))/(n(SO_2)) = (1/32)/(1/64) = 2/1$

Answer 2 · 2017-06-01T07:45:09

2 : 1

Explanation:

Molar Mass of $O_{2}$ $O_2$ = 32 $g m o l^{- 1}$ $g mol^-1$
$\Rightarrow$ $rArr$ 1 g of $O_{2}$ $O_2$ = $\frac{1}{32} m o l$ $1/32 mol$

And Molar Mass of $S O_{2}$ $SO_2$ = $32 + 2 \cdot 16 g m o l^{- 1} = 64 g m o l^{- 1}$ $32 + 2 * 16 g mol^-1 = 64 g mol^-1$
$\Rightarrow$ $rArr$ 1 g of $S O_{2}$ $SO_2$ = $\frac{1}{64} m o l$ $1/64 mol$

Hence, $O_{2} : S O_{2}$ $O_2 : SO_2$
$\Rightarrow$ $rArr$ $\frac{1}{32} N_{A} : \frac{1}{64} N_{A}$ $1/32 N_A : 1/64 N_A$
$\Rightarrow$ $rArr$ $2 : 1$ $2 : 1$

Science

Math

Humanities

... and beyond

Question #98339

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question