Question #302ef

1 Answer
Jacob T.
May 25, 2017

#DeltaH=-110.0# #kJ#/#mol# #CO#

Explanation:

First, write the reaction formulas.
#C(s)+O_2(g)->CO_2(g)#, #DeltaH_1=-393.5kJ*mol^-1# (1)
#2CO(s)+O_2(g)->2CO_2(g)#, #DeltaH_2=2*(-283.5)kJ*mol^-1# (2)

The formula for the formation of carbon monoxide #CO#:
#C(s)+1/2O_2->CO(g)#

Apply the Hess's law to find the enthalpy of formation of #CO#:
#DeltaH_1#-#DeltaH_2#
#=-393.5 kJ*mol^-1-(-283.5kJ*mol^-1)#
#=-110.0kJ*mol^-1#

Related questions
See all questions in Enthalpy
Impact of this question
2844 views around the world
You can reuse this answer
Creative Commons License