Question #302ef

1 Answer
Jacob T.
May 25, 2017

DeltaH=-110.0 kJ/mol CO

Explanation:

First, write the reaction formulas.
C(s)+O_2(g)->CO_2(g), DeltaH_1=-393.5kJ*mol^-1 (1)
2CO(s)+O_2(g)->2CO_2(g), DeltaH_2=2*(-283.5)kJ*mol^-1 (2)

The formula for the formation of carbon monoxide CO:
C(s)+1/2O_2->CO(g)

Apply the Hess's law to find the enthalpy of formation of CO:
DeltaH_1-DeltaH_2
=-393.5 kJ*mol^-1-(-283.5kJ*mol^-1)
=-110.0kJ*mol^-1

Related questions
See all questions in Enthalpy
Impact of this question
2997 views around the world
You can reuse this answer
Creative Commons License