Question #9db85

1 Answer
May 20, 2017

9 * 10^5"g"

Explanation:

In order to be able to answer this question, you must know the enthalpy of fusion of water

DeltaH_"fus" = "333.55 J g"^(-1)

The enthalpy of fusion tells you the amount of energy needed in order to convert "1 g" of a given substance from solid at its melting point to liquid at its melting point.

In your case, you know that in order to convert "1 g" of ice at 0^@"C" to liquid water at 0^@"C", you need to provide "333.55 J".

You can thus say that 3 * 10^8 "J" of heat will melt

3 * 10^8 color(red)(cancel(color(black)("J"))) * "1 g ice"/(333.55color(red)(cancel(color(black)("J")))) = color(darkgreen)(ul(color(black)(9 * 10^5color(white)(.)"g ice")))

The answer is rounded to one significant figure.

If you want, you can convert this to kilograms by using the fact that

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