Question #69eae

1 Answer
anor277
May 17, 2017

#"Dissociate............."#

Explanation:

The strength of an acid relates to the extent which the following equilibrium is completed:

#HX(aq) + H_2O(l) rightleftharpoonsH_3O^(+) + X^-#

For strong acids, #X^(-) =HSO_4^-, "halide" (X!=F), ClO_4^-#, the equilibrium lies STRONGLY to the right. For weaker acids, #HF, H_2SO_3, HO_2C-CH_3#, the equilibrium lies to the left.

And this we can use the equilibrium constant, #K_a#, as a determinant:

#K_a=([H_3O^+][X^-])/([HX])#

The given acids, have #K_a# values so large in water that the dissociation is considered to be quantitative.

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