Question #82f6e

1 Answer
Nathan L.
May 17, 2017

#K# is being oxidized,
#Cu# is being reduced

Explanation:

Since oxidation is the gain in oxidation state (loss of electrons), #K# is being oxidized because it has on oxidation state of #0# originally, and as the reaction proceeds, its oxidation state is raised to #+1#.

Since reduction is the lowering in oxidation state (gain of electrons), #Cu# is being reduced because it has on oxidation state of #+2# originally, and as the reaction proceeds, its oxidation state is lowered to #0# from becoming pure #Cu#.

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