Question #49a06

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Answer 1 · 2017-05-14T09:05:37

Here's my explanation

$"displacement" = 1/2gt^2 = "5m"$

$Vavg = "5m/s"$

$Vavg = (V_o + V_f)/2$

$V_o + V_f = 10$

$V_o = "gt "(where t is free fall time -1)$

$Vf = 10 - 10t$

$Vf = g(t+1) = 10t + 10$

$Vf = 10-10t = 10t + 10$

$t = 0+1$

$t = 1s$

If the height of the tower is h

$"Average speed" = h/s$