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What reaction yields hydrogen gas from magnesium metal and water?

1 Answer

May 14, 2017

A redox reaction..........

Explanation:

The metal is oxidized to $M g^{2 +}$ $Mg^(2+)$ :

$M g (s) \to M g^{2 +} + 2 e^{-}$ $Mg(s) rarr Mg^(2+) + 2e^(-)$

Steam is reduced to dihydrogen gas:

$H_{2} O + 2 e^{-} \to O^{2 -} + H_{2} (g)$ $H_2O + 2e^(-) rarr O^(2-) + H_2(g)$

Adds them together:

$M g (s) + H_{2} O (g) \to M g O (s) + H_{2} (g)$ $Mg(s) + H_2O(g) rarr MgO(s) + H_2(g)$

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