What is the elemental composition of $H_{3} P O_{4}$ $H_3PO_4$ ?

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What is the elemental composition of $H_{3} P O_{4}$ $H_3PO_4$ ?

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Answer 1 · 2017-05-13T15:08:57

Well we can quote the elemental composition...........

Explanation:

$% composition = \frac{Atomic mass}{Molecular mass} \times 100 %$ $"% composition"="Atomic mass"/"Molecular mass"xx100%$

$% H = \frac{3 \times 1.00794 \cdot g \cdot m o l^{- 1}}{97.99 \cdot g \cdot m o l^{- 1}} \times 100 % = 3.1 % .$ $%H=(3xx1.00794*g*mol^-1)/(97.99*g*mol^-1)xx100%=3.1%.$

$% P = \frac{30.9737 \cdot g \cdot m o l^{- 1}}{97.99 \cdot g \cdot m o l^{- 1}} \times 100 % = 31.6 % .$ $%P=(30.9737*g*mol^-1)/(97.99*g*mol^-1)xx100%=31.6%.$

$% O = \frac{4 \times 15.999 \cdot g \cdot m o l^{- 1}}{97.99 \cdot g \cdot m o l^{- 1}} \times 100 % = 65.3 % .$ $%O=(4xx15.999*g*mol^-1)/(97.99*g*mol^-1)xx100%=65.3%.$

Do the elemental percentages sum up to $100 %$ $100%$ ? Should they?

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What is the elemental composition of $H_{3} P O_{4}$ $H_3PO_4$ ?

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