What is the $pH$ of an aqueous solution in which $[HO^-]=0.041molL^-1$ ?

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Answer 1 · 2017-05-10T16:32:05

$pH=12.6$

We know that in aqueous solution under standard conditions.....

$pH+pOH=14$ .

And $pOH=-log_(10)[HO^-]$ ; so here $pOH=-log_10(0.041)=$

$-log_(10)0.041=-(-1.39)=1.39$ .

And thus $pH=14-pOH=12.6$

So is this solution acid or alkaline?

What is the pHpH of an aqueous solution in which [HO^-]=0.041*mol*L^-1[HO^-]=0.041*mol*L^-1?