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Answer 1 · 2017-05-10T03:23:47

NaOH is a strong base and HCl is a strong acid. To neutralise one mole of acid , we will equal volume of one mole of base ( NaOH).

Using this fact we can write

number of moles of HCl react will be equal to the number of moles of NaOH.

number of moles of HCl = molarity of HCl x Volume of HCl ........ (a)

number of moles of NaOH = molarity of NaOH x Volume of NaOH ....(b)

using (a) and (b) we get,

molarity of HCl x Volume of HCl = molarity of NaOH x Volume of NaOH

40.0 mL x 0.20 M = 0.25 M x #V_NaOH#

#V_NaOH# = 40 mL x 0.20 M / 0.25 M

#V_NaOH# = 32 mL