#8934*g# of oxygen gas is reacted with stoichiometric zinc sulfide. What mass of zinc oxide results?

1 Answer
anor277
May 10, 2017

We interrogate the reaction............and get a mass of over #18*kg# with respect to #"zinc oxide"#.

Explanation:

#2ZnS(s) + 3O_2(g) rarr 2ZnO(s) + 2SO_2(g)#

#"Moles of dioxygen"=(8934*g)/(32.00*g*mol^-1)=279.2*mol#.

And thus we represent an equivalent quantity of #"zinc sulfide"# as #279.2*molxx2/3=186.1*mol#; this quantity follows PRECISELY the stoichiometry of the given equation. Agreed?

i.e. #186.1*molxx97.47*g*mol^-1="over 18"*kg#.

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