If a number, #x# is increased by 24% then what is the percentage increase in #x^2#?

Question

2339 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-03T18:25:16

#53.76%#

We have the original number #x#, and its square #x^2#

If this number is increased by #24%# then the new value is:

# x+24/100x = 124/100x = 31/25x#

So the new square is:

# (31/25x)^2 = 961/625x^2 #

So then the net increase in the square is:

# 961/625x^2 - x^2 = 336/625 x^2#

And the percentage increase is given by:

# 336/625 x^2 * 1/x^2 * 100 = 1344/25=53.76%#