What is the #"VSEPR"# treatment of #"hydrazine"#?

1 Answer
anor277
May 1, 2017

There are #4xx1+2xx7=18*"electrons"# to distribute around 6 centres........

Explanation:

And so for hydrazine, we write,

#H_2ddotN-ddotNH_2#; these represent 14 valence electrons, #4xxN-H#, and #1xxN-N#, and #2xxN# lone pairs.

The remaining 4 electrons are conceived to be the inner core electrons on the nitrogen centre (i.e. the original #1s^2# sets). Anyway, we have distributed 18 electrons as required, 14 are valence electrons. Capisce?

What is the geometry about the nitrogen centres?

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