Question #eb3dd

1 Answer
Anuj Baskota
May 1, 2017

206.00 kJ mol^(-1)

Explanation:

The formula to calculate the heat change of a reaction is
ΔH = -mcΔT (where m is the mass of the fluid whose temperature changes which in this case is water, c is the specific heat capacity of water and ΔT is the change in temperature of water)

Heat change when 0.025 mol of Na is added
= -100 * 4.18*(35.75-25.00)
= -5138.5 J

Now this is heat change for 0.025 mole of Na.
Enthalpy change means you have to calculate the heat change for 1 mole.

So enthalpy change for 1 mole of Na is -5138.5/0.025 = 205540 J= 206.00 kJ mol^(-1)

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